When speed is increased by a factor of three,
New speed v'= 3v where v is the initial speed
a) Momentum P= mv
So new momentum P'= mv'= m*3v= 3 mv= 3P
So momentum increases by a factor of three
b) Kinetic Energy KE=m(v^2)/2
New Kinetic Energy KE'= m(v'^2)/2= m((3v)^2)/2= 9 m(v^2)/2= 9 KE
Therefore kinetic energy increases by a factor of 9
(20%) Problem 2: An object's speed is increased by a factor of three. > 50% Part...
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For part c, I tried -242 and +242 and I still got it
incorrect.
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