Question

Group# Course/Section Instructor Tables 1 (15 points) Force F Experimental Mass (kg) Force (N) 0.050 SA 0.100 1024 1.373 Direction 20.0° 90.0 Equilibrant Fu Resultant Fri 249.2°C ZUL Graphical Solution Force Force (N) Direction 20.0° FT 980 Resultant Fri 1.237 Go CD 90.0° Analytical Solution Force Force (N) X-component y -component F Direction 20.0° 90.0° Resultant FR2 Part 1: Error Calculations (15 points) % Error of magnitude for Experimental compared to Analytical = % Error of direction for Experimental compared to Analytical = % Error of magnitude Graphical compared to Analytical = % Error of direction Graphical compared to Analytical = je se

Answer 1

Analytical force = mg = mx9-8m/52 Fosee T fosecco Direction R-componenty.component y fi 0:49 | 20° 0:46 N 0.168N 2 10.98 | 90° TON 10.98 Resultant 1.5461681149 146g 11.476NK fx= mgcoso 10-20, 90 fy=masino [m=0005,ol! tino = y 0-tar(89)"

y.error Experimental ts Analytical (forsee) TRE- TRA T of experiment RA A X100 Reis resultant = 11-323-1.5461 Rais resultant 10546 xlop af Analytical = 14.424% Y. error direction Erepormental to Analytical = | OE-OAK [OA is angle of resultant I OA lot from Analytical OE is angle of resultant from Expenmental] 168.2-68.1141 1 88,114 M = 0.1264 V. error for graphicalt | Rae Balcon RA = 102315 4/2103 =19:35

Rais Resultant of graphical y error of direction for graphical = 0.167% OG is eingle of resultant from hraphical solution