Question

•Write a java program to read 10 numbers and print them in reverse order. Modify your program to work for N numbers given by the user Extend your program to find the average of these numbers Extend your program to find the smallest number of these numbers Extend your program to find the largest number of these numbers

•Write a program to read 10 numbers and print them in reverse order. Modify your program to work for N numbers given by the user Extend your program to find the average of these numbers Extend your program to find the smallest number of these numbers Extend your program to find the largest number of these numbers

Answer 1

Answer:

a) Program to read 10 numbers and print in reverse order:

#include <iostream>
using namespace std;

int main()
{
  
int a[10];
cout<<"Enter 10 numbers: "<<endl;
  
for(int i=0; i<10; i++)
{
cin>>a[i];
}
  
cout<<"Reverse order: ";
for(int i=9; i>=0; i--)
{
cout<<a[i]<<" ";
}
cout<<endl;
  
  

return 0;
}

Output:

Enter 10 numbers: 10 Reverse order: 10 9 8 7 6 5 4 3 2 1

b) Modification for N numbers by user:

#include <iostream>
using namespace std;

int main()
{
int n;
cout<<"Enter the number of numbers you want to enter: ";
cin>>n;
int a[n];
cout<<"Enter numbers: "<<endl;
  
for(int i=0; i<n; i++)
{
cin>>a[i];
}
  
cout<<"Reverse order: ";
for(int i=n-1; i>=0; i--)
{
cout<<a[i]<<" ";
}
cout<<endl;
  
  

return 0;
}

Output:

Enter the number of numbers you want to enter: 5 Enter numbers: Reverse order: 5 4 3 2 1

c) Extended program to find average of these numbers:

#include <iostream>
using namespace std;

int main()
{
int n;
cout<<"Enter the number of numbers you want to enter: ";
cin>>n;
int a[n];
cout<<"Enter numbers: "<<endl;
  
for(int i=0; i<n; i++)
{
cin>>a[i];
}
  
cout<<"Reverse order: ";
  
float avg=0.0;
  
for(int i=n-1; i>=0; i--)
{
cout<<a[i]<<" ";
avg = avg + (float)a[i];
}
  
avg = avg/(float)n;
  
cout<<"Average: "<<avg<<endl;
cout<<endl;
  
  

return 0;
}

Output:

Enter the number of numbers you want to enter: 5 Enter numbers: Reverse order: 3 2 4 3 2 Average: 2.8

d) Extended program for smallest number:

#include <iostream>
using namespace std;

int main()
{
int n;
cout<<"Enter the number of numbers you want to enter: ";
cin>>n;
int a[n];
cout<<"Enter numbers: "<<endl;
  
for(int i=0; i<n; i++)
{
cin>>a[i];
}
  
cout<<"Reverse order: ";
  
float avg=0.0;
  
for(int i=n-1; i>=0; i--)
{
cout<<a[i]<<" ";
avg = avg + (float)a[i];
}
  
avg = avg/(float)n;
  
cout<<endl;
  
cout<<"Average: "<<avg<<endl;
  
int min=a[0];
  
for(int i=0; i<n; i++)
{
if(a[i]<min)
{
min=a[i];
}
}
cout<<"Smallest number: "<<min<<endl;
  
  
  
  

return 0;
}

Output:

Enter the number of numbers you want to enter: 5 Enter numbers: 32 Reverse order: 2 32 4 3 2 Average: 8.6 Smallest number: 2

e) Extended program for largest number:

#include <iostream>
using namespace std;

int main()
{
int n;
cout<<"Enter the number of numbers you want to enter: ";
cin>>n;
int a[n];
cout<<"Enter numbers: "<<endl;
  
for(int i=0; i<n; i++)
{
cin>>a[i];
}
  
cout<<"Reverse order: ";
  
float avg=0.0;
  
for(int i=n-1; i>=0; i--)
{
cout<<a[i]<<" ";
avg = avg + (float)a[i];
}
  
avg = avg/(float)n;
  
cout<<endl;
  
cout<<"Average: "<<avg<<endl;
  
int min=a[0];
  
for(int i=0; i<n; i++)
{
if(a[i]<min)
{
min=a[i];
}
}
cout<<"Smallest number: "<<min<<endl;
  
int max=a[0];
  
for(int i=0; i<n; i++)
{
if(a[i]>max)
{
max=a[i];
}
}
cout<<"Largest number: "<<max<<endl;
  
  
  
  

return 0;
}

Output:

Enter the number of numbers you want to enter: 5 Enter numbers: Reverse order: 11 2 4 3 2 Average: 4.4 Smallest number: 2 Largest number: 11

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