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5) If a couple plans to have eleven children, how many gender sequences are possuble A) 11 C) 2048 B) 121 D) 2.853116706e 11
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Answer #1

5)

If a couple plans to have eleven children.

Number of gender sequence are possible = 2^11 = 2048

C) 2048

6)

The regression equation is \hat{y} = - 1.04x + 50.3

Slope = - 1.04

Slope is negative so the correlation also negative.

The correct option is

B) Negative linear correlation.

7)

We have to find the correlation coefficient ( r ) .

Formula is

r=\frac{n\sum xy-(\sum x)(\sum y)}{\sqrt{[n\sum x^{2}-(\sum x)^{2}][n\sum y^{2}-(\sum y)^{2}]}}

n = 9

x y xy x^2 y^2
10.4 52.5 546 108.16 2756.25
8.7 48.2 419.34 75.69 2323.24
13.3 60.8 808.64 176.89 3696.64
12.4 61 756.4 153.76 3721
18.7 84.4 1578.28 349.69 7123.36
10.2 51.2 522.24 104.04 2621.44
6.9 33.9 233.91 47.61 1149.21
15.5 78 1209 240.25 6084
15.9 80.8 1284.72 252.81 6528.64
Total 112 550.8 7358.53 1508.9 36003.78

r=\frac{9*7358.53-(112)(550.8)}{\sqrt{[9*1508.9-(112)^{2}][9*36003.78-(550.8)^{2}]}}

r=\frac{4537.17}{\sqrt{[1036.1][20653.38]}} =0.981

A) 0.981

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