Question

principles of chemistry 122

6. A bottle of wine contains 750.0 mL of wine. If the wine is 12.00% are in the bottle of wine? V of alcohol ->X ) alcohol, bow ml of alice 12 .00 100 150 >> x=(12*50) 90 mL loo 7. A mixture of alcohol and water is 28.00%(v/v) alcohol. How many of the mixture do I need in order to have 250.0 mL of alcohol? 8. A mixture of salt and water is 28.0 g salt and 60.0 g water. What is the % (m/m) salt? I might or me

Answer 1

7 6. The wine is 12.007. (v/v) alcohol. So, 100mL wire contains 12 mL of alcohol 750me of wine contains (750x12) - 90 mL of alconul 100 7 A mixture of alcohol and water is 28.00% (v/v) alcohol this means 100 mL of the mixture contains 28mL of alcohol 28mL of alcohol present in 100 mL mixture : 250m2" "" " 250x100N 20 mL van 892.9 mL mixture = 0892901 1000 = 0.8929 L So 0.8929L of the mixture I need in order to have 250 mL of alcohol. A mixture of salt and water is 28-09 and Go.g water sostotal weight of the mixture 88 g 90 088 g of mixture contains 28g of salt 100g " " . (28x100 ) :. 31.81% (m/m) salt = 31.81% 88