Consider the following data for compound A: (delta)Hf(kj/mol) S(J/K*mol) A(s) -224.57 32.36 A(l) -172.45 109.55 Use...

Question

Question

Consider the following data for compound A:

(delta)Hf(kj/mol) S(J/K*mol)

A(s) -224.57 32.36

A(l) -172.45 109.55

Use these data to determine the normal freezing point of compound A. Report your answer to 3 significant figures and degrees Celsius)

Freezing point =

Answer 1

Answer #1

Change in enthalpy = -172.45 -(-224.57) = 52.12 kJ/mol

Change in entropy = 109.55 - 32.36 = 77.19 J/mol K

at phase equilibrium delta G = 0

delta G = delta H - T x delta S

0 = 52.12 kJ/mol - T* 77.19 J/mol K

T = 52120 / 77.19

= 675.21 K

= 402 ^oC

Answer 2

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