please provide detailed explanation. I have a good grasp of the concept but I'm just trying to see where I went wrong on this problem.
I was able to plug in everything but my pvalue is incorrect.
If possible can someone include the rstudio code to do this problem.
The test statistic t = ()/sqrt(s1^2/n1 + s2^2/n2)
= (3422 - 3255)/sqrt((468)^2/31 + (642)^2/35) = 1.217
DF = ((468)^2/31 + (642)^2/35)^2/(((468)^2/31)^2/30 + ((642)^2/35)^2/34) = 62
P-VALUE = P(T > 1.217)
= 1 - P(T < 1.217)
= 1 - 0.8859 = 0.1141
As the p-value is greater than the significance level (0.1135 > 0.05), so the null hypothesis is not rejected.
Option-B is correct.
please provide detailed explanation. I have a good grasp of the concept but I'm just trying...
Question 11 A national computer retailer believes that the average sales are greater for salespersons with a college degree. A random sample of 35 salespersons with a degree had an average weekly sale of S3455 last year, while 32 salespersons without a college degree averaged S3155 in weekly sales. The standard deviations were $468 and 5642 respectively. Is there evidence at the 5% level to support the retailer's belief? Select the p-value, Decision to Reject (RH) or Failure to Reject...