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TV channel 2 broadcasts in the frequency range 54 to 60 MHz. (a) Find the energy...

TV channel 2 broadcasts in the frequency range 54 to 60 MHz.

(a) Find the energy of the average photon emitted.


(b) If the power of the broadcast is 53,290 W, how many photons are emitted per second?
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Answer #1

eney, f2 = 54 M13 - 54 x 10 13. The lowest frequency of = 54 MHz = 50 . The highest frequency, fit= 60 MHz = 60 * 10 Hz - (a

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