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An article reported that for a sample of 20 kitchens with gas cooking appliances monitored during a one-week period, the samp

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Answer #1

Sol

Given

n = 20

Mean = 654.16

S.D ( s ) = 164.43

95% Confidence interval

Alpha = 1 - 0.95

Alpha = 0.05

Alpha / 2 = 0.05/2

Alpha /2 = 0.025

95% confidence interval

C.I = MEAN +/- Z ( 0.025 ) * S / ✓N

OPTION B IS CORRECT

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