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Develop a linear programming model for this problem. (Do Not Solve The Problem Warehouse City E City. E City G City H Warehou

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Answer #1

Let the no. of units shipped from Warehouse A to City E be Xae, Warehouse A to City f be Xaf and so on. Hence, we get the decision variables as Xae, Xaf, Xag, Xah, Xbe, Xbf, Xbg, Xbh, Xce, Xcf, Xcg, Xch, Xde, Xdf, Xdg, Xdh

Total cost = 0.53*Xae + 0.21*Xaf + 0.52*Xag + 0.41*Xah + 0.31*Xbe + 0.38*Xbf + 0.41*Xbg + 0.29*Xbh + 0.56*Xce + 0.32*Xcf + 0.54*Xcg + 0.33*Xch + 0.42*Xde + 0.55*Xdf + 0.34*Xdg + 0.52*Xdh

We have to minimize this total cost. Hence, we get the objective function as:

Minimize Total Cost C = 0.53*Xae + 0.21*Xaf + 0.52*Xag + 0.41*Xah + 0.31*Xbe + 0.38*Xbf + 0.41*Xbg + 0.29*Xbh + 0.56*Xce + 0.32*Xcf + 0.54*Xcg + 0.33*Xch + 0.42*Xde + 0.55*Xdf + 0.34*Xdg + 0.52*Xdh

Total Supply = 4000 + 6000 + 4000 + 5500 = 19,500

Total Demand = 3400 + 2000 + 6500 + 5750 = 17,650‬

Total Demand < Total Supply. Hence, this is an unbalanced problem. We will have "<=" sign in supply constraints

Subject to Supply Constraints:

Xae + Xaf + Xag + Xah <= 4000................Constraint for supply from Warehouse A

Xbe + Xbf + Xbg + Xbh <= 6000................Constraint for supply from Warehouse B

Xce + Xcf + Xcg + Xch <= 4000................Constraint for supply from Warehouse C

Xde + Xdf + Xdg + Xdh <= 5500................Constraint for supply from Warehouse D

Xae + Xbe + Xce + Xde = 3400................Constraint for Demand at City E

Xaf + Xbf + Xcf + Xdf = 2000...................Constraint for Demand at City F

Xag + Xbg + Xcg + Xdg = 6500................Constraint for Demand at City G

Xah + Xbh + Xch + Xdh = 5750................Constraint for Demand at City H

Xae, Xaf, Xag, Xah, Xbe, Xbf, Xbg, Xbh, Xce, Xcf, Xcg, Xch, Xde, Xdf, Xdg, Xdh >= 0........Non-negativity constraints as no. of units cannot be negative

The above formulation is complete.

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