Question

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4) Delete set of keys from Python Dictionary Given: sampleDict = { "name": "Kelly", "age":25, "salary" : 8000, "city": "New york" } keysToRemove = ["name", "salary"] Expected output: {'city': 'New york', 'age': 25}

Answer 1

I have uploaded the Images of the code, Typed code and Output of the Code. I have provided explanation using comments(read them for better understanding).

Delete set of keys from Python Dictionary

Images of the Code:

Note: If the below code is missing indentation please refer code Images

1 #Delete set of keys from Python Dictionary 2 #initializing Dictionary 3 sampleDict = { 4 "name": "Kelly", 5 "age":25, 6 "salary" : 8000, 7 "city": "New york" 8 } 9 #keys to remove 10 keysToRemove = ["name", "salary"] 11 #for Loop will iterate 2 times because keysToRemove has 2 elements 12 #for every iteration, one value from keysToRemove is assigned to i 13 - for i in keysToRemove: 14 #if that į value is in sampleDict 15 if i in sampleDict: 16 #Delete the value 17 del sampleDict[i] 18 #printing the sampleDict print(sampleDict) 20

Typed Code:

#Delete set of keys from Python Dictionary
#initializing Dictionary
sampleDict = {
"name": "Kelly",
"age":25,
"salary": 8000,
"city": "New york"
}
#keys to remove
keysToRemove = ["name", "salary"]
#for loop will iterate 2 times because keysToRemove has 2 elements
#for every iteration, one value from keysToRemove is assigned to i
for i in keysToRemove:
#if that i value is in sampleDict
if i in sampleDict:
#Delete the value
del sampleDict[i]
#printing the sampleDict
print(sampleDict)
//code ended here

Output:

{'city': 'New york', 'age': 25}

Iterate over dictionaries using for loops

Images of the Code:

Note: If the below code is missing indentation please refer code Images

1 #Iterate over dictionaries using for Loops 2 d = {'X':1, 'y':2, 'z':3} 3 #for Loop will iterate 3 times because 3 items in di 4 #for every iteration, one key and one value is assigned to key, value 5 #sorted is used to sort the items in an order for key, value in sorted(d.items()): 7 #printing key and value 8 print(key,"->", value)

Typed Code:

#Iterate over dictionaries using for loops   
#Initializing Dictionary
d = {'x':1, 'y':2, 'z':3}
#for loop will iterate 3 times because 3 items in d
#for every iteration, one key and one value is assigned to key,value
#sorted is used to sorts the items in an order
for key,value in sorted(d.items()):
#printing key and value
print(key,"->",value)
//code ended here

Output:

x -> 1 y -> 2 z -> 3

get maximum and minimum values in a Dictionary

Images of the Code:

Note: If the below code is missing indentation please refer code Images

1 #get maximum and minimum values in a Dictionary 2 my_dict = {'x':500, 'y':5874, 'z':560} 3 #taking values to val val = my_dict.values() 5 #finding Maximum value in it 6 maximum = max(val) 7 #finding Minimum value in it 8 minimum = min(val) 9 #printing Maximum and Minimum value 10 print("Maximum value: ", maximum) 11 print("Minimum value: ",minimum)

Typed Code:

#get maximum and minimum values in a Dictionary
my_dict = {'x':500, 'y':5874, 'z':560}
#taking values to val
val = my_dict.values()
#finding Maximum value in it
maximum = max(val)
#finding Minimum value in it
minimum = min(val)
#printing Maximum and Minimum value
print("Maximum value: ",maximum)
print("Minimum value: ",minimum)
//code ended here

Output:

Maximum value: 5874 Minimum value: 500

change Brad's salary to 8500

Images of the Code:

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1 #change Brad's salary to 8500 2 #initializing Dictionary 3 sampleDict = { 4 'empl': {'name': 'Jhon', 'salary': 7500}, 5 emp2': {'name': 'Emma', 'salary': 8000}, 6 'emp3': {'name': 'Brad', 'salary': 6500} 7 } 8 #changing salary to 8500 9 sampleDict['emp3']['salary'] = 8500 #printing sampleDict 11 print(sampleDict) 12

Typed Code:

#change Brad's salary to 8500
#initializing Dictionary
sampleDict = {
'emp1': {'name': 'Jhon', 'salary': 7500},
'emp2': {'name': 'Emma', 'salary': 8000},
'emp3': {'name': 'Brad', 'salary': 6500}
}
#changing salary to 8500
sampleDict['emp3']['salary'] = 8500
#printing sampleDict
print(sampleDict)
//code ended here

Output:

{'empl': {'name': 'Jhon', 'salary': 7500}, 'emp2': {'name': 'Emma', 'salary': 8000}, 'emp3': {'name': 'Brad', 'salary': 8500}}

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