(graded) Section 3.6: Variation of Parameters ITEMS SUMMARY Try again You have answered 1 out of...
5. Try again < Previous You have answered 1 out of 3 parts correctly. Consider the differential equation: y" +625y = sec (25x). a. Find the general solution to the corresponding homogeneous equation. In your answer, use ci and cy to denote arbitrary constants. Enter cı as c1 and ca as c2. Ye = cl cos(25x) + c2 sin (25x) b. Apply variation of parameters to find a particular solution. Yp = 625 In ( cos(25x)) cos(25x) + mars -x...
Please show how to solve. Correct answer shown. Use variation of parameters to find a general solution to the differential equation given that the functions y, and y2 are linearly independent solutions to the corresponding homogeneous equation for t>0. - 2t + ty +(2t - 1)x - 2y =ềe -2t, Y1 = 2t - 1, y2 = e - A general solution is y(t) = X X That's incorrect. 1 Correct answer: C1(2t - 1) + c2 e - 2t...
(graded) Section 7.7: Fundamental Matrices ntial Try again pring You have answered 1 out of 3 parts correctly. Consider the system of equations given by: x'= a. Find a fundamental matrix for the system. eor X(t) = b. Find the matrix exponential, y(t) = M, of the system. (t)- c. Solve the initial value problem with a(0) using the matrix exponential found in Part b. (t)
Chapter 3, Section 3.6, Question 02 Use the method of variation of parameters to find a particular solution of the differential equation Y (t) ак
In this problem you will use variation of parameters to solve the nonhomogeneous equation fy" + 4ty' + 2y = 1 + 12 A. Plug y = p into the associated homogeneous equation (with "0" instead of "13 + 12") to get an equation with only t and n. (Note: Do not cancel out the t, or webwork won't accept your answer!) B. Solve the equation above for n (uset # 0 to cancel out the t). You should get...
Note that yı(t) = Vt and yz(t) = t-1 are solutions of the linear homogeneous differential equation 2t’y" + 3ty' – y = 0. Use variation of parameters to find the general solution of the nonhomogeneous differential equation 2t’y" + 3ty' - y = 4t² + 4t. 8 o* Civt + Cat-1 + + 35 OB. 4 Civt + Cat-1+ t + 2 t2 9 of Civt + Cat-1 + t2 + 2t 9 00 Civt + Cut-+ 4 OE...
QUESTION 10 Note that yı(t) Vt and y(t) =t-1 are solutions of the linear homogeneous differential equation 2t²Y" + 3ty' – y=0. Use variation of parameters to find the general solution of the nonhomogeneous differential equation 2t’y" + 3ty' - y = 4t? + 4t. 8 2 OA Civt + Cat-1 + 74 35 oCivt+Cet-1 + 4 9 t2 + 2t OC Civt + Cat-1 + 4 9 t2 + 2 5 2 OD. 8 Civt + Cat-1 + t2...