Question

Two routes connect an origin and destination with performance functions t1 = 5 + 3x1 and t2 = 7 + X2, with ts in minutes and

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Answer #1

We have two routes from A to B

Route 1 - has x1 (thousands of vehicles) and at ravel time of 5 +3x1

Route 2 - has x2 (thousands of vehicles) and at ravel time of 7 +x2

For user equilibrium we know that the Z function is

where t(x1) = 5 +3x1 and t(x2) = 7 +x2

Also we know that x1 + x2 = 7

only two paths so the travel time should also be equal

therefore

5 +3x1 = 7 +x2

So solving for x1 and x2 we get x1= 2.25 and x2 = 4.75

Therefore 2250 vehicles travel on Route 1 and 4750 vehicles travel on Route 2

Now that we know flows, we can calculate the ESALS.

WE know the vehicle composition by vehicle type. This is shown below.

Vehicle Composition cars 6100 0.871429 buses 800 0.114286 trucks 1001 0.014286 7000

So for each route, we can calculate the number of cars, buses and trucks as follows

Total vehicles 2250 Cars 1960.71 4139.29 Buses 257.14 542.86 Trucks 32.14 67.86 4750

We know that for each vehicle type the # of kips is as follows

Cars 2 Buses 2 Trucks 80 kips

So calculate the kips on each route as follows and hence the ESALS

1 ESAL = 18 kips

so for route 1 we have

1960.71*2 + 257.14 * 2 + 32.14 * 80 = 7007.143 kips = 7007.143/18 = 389.286 ESAL

so for route 2 we have

4139.29*2 + 542.86*2 + 67.86*80 = 14792.86 kips = 921.825 ESAL

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