Question

3B) (30 points) The following metals have energies of formation of vacancies and melting points respectively given below: Element Qv eV Tm melting point, oC Pd 1.0 (1555 - Cu 0.7 1085 1.6 1768 a) Determine the vacancy concentration of each element in its melting point. (15) D) Calculate the mean separation of vacancies and show that at the melting point approximately the separation is the same. (15) Ny/N=exp(-Qv/RT) where KB=8.62 x 10-5 eV/atom K Pt

Answer 1

Ni 8.473 102007 ) Nu = 4.7x10 23 vacancies/m3 For.pt 8 = 22.45 9mm Apt = 195.084 N=SNA = 6.023x102² x 21045 106 Apt 195.084 N=606281028 afone W = 6.62x10?* exp (-306 - 18.41 x 1023 oforma