Here, Object of interface Iparent is created and named as ' p ' and constructor of class Child is called with the parameters 1, 2.
Therefore, a becomes 1 and b becomes 2. Now inside the constructor y = b . => y becomes 2.
The print function of class Child is called with the object of interface Iparent. => Child y => Child 2 will be printed.
Therefore, the second option 'Child 2' is correct.
Question 28 public class Main public static void main(String args[]) { Iparentp=new Child (1.2); p.printo: interface...
What is the Java output? Part One: class Driver { public static void main(String[] args) { int a = 5; int b = 3; if (a < b || a * 2 < b) System.out.print(a - b); System.out.print(b + a); } } Part Two: class Driver { public static void main(String[] args) { int a = 5; int b = 8; if (a < b) if (a * 2 < b) System.out.print("foo"); else System.out.print("bar"); else System.out.print("buz"); } }
Revision Question Consider the following Java class: { public static void main (String [ ] args) { ArrayQueue<Integer> queue; queue = new ArrayQueue<Integer> () ; Integer x, y ; x = 3; y = 6; queue.offer (x) ; queue.offer (12) ; queue.offer (y) ; y = queue.peek () ; queue.poll () ; queue. offer (x - 2) ; queue.offer (x) ; queue.offer (y + 4) ; System.out.println ("Queue Elements: ") ; while (! queue.empty() ) System.out.print (queue.poll () + "...
What output is produced by the following program? public class MysteryNums public static void main(String[] args) - int x = 12; int y = x - 3; 3, sentence (y, x + y); . public static void sentence (int numi, int num2) { 4: System.out.println(num1 + " + num2);
1. Analyze the following code: public class Test implements Runnable { public static void main(String[] args) { Thread t = new Thread(this); t.start(); } public void run() { System.out.println("test"); } } 1. The code compiles but will not print anything since t does not invoke the run method. 2. The code will not compile since you cannot invoke "this" in a static method. 3. The program compiles, runs, and prints tests on the console. 2. What will the following example...
import java.util.Scanner; public class TriangleMaker { public static void main(String[] args) { // TODO Auto-generated method stub System.out.println("Welcome to the Triangle Maker! Enter the size of the triangle."); Scanner keyboard = new Scanner(System.in); int size = keyboard.nextInt(); for (int i = 1; i <= size; i++) { for (int j = 0; j < i; j++) { System.out.print("*"); } System.out.println(); } for (int...
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } The variable t is private and therefore cannot be accessed in the main method. The program compiles and runs fine. t is non-static and it cannot be referenced in a static context in the main method. The variablet is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
10. What prints when the following code is executed? public static void main (String args) "Cattywampus"; for (int i-s.length )-1 i> 0 i-2) if (s.charAt (i)a') System.out.print(""); ] else if (s.charAt (i)'t') System.out.print (s.charAt (i-2)) i+ti else System. out. print (s . charAt (İ) ) ; if (i<2) System.out.print ("y"); System.out.println () 10. What prints when the following code is executed? public static void main (String args) "Cattywampus"; for (int i-s.length )-1 i> 0 i-2) if (s.charAt (i)a') System.out.print(""); ]...
Analyze the following code: public class Test { private int t; public static void main(String[] args) { int x; System.out.println(t); } } t is non-static and it cannot be referenced in a static context in the main method. The program compiles and runs fine. The variable t is not initialized and therefore causes errors. The variable x is not initialized and therefore causes errors.
what is output public static void main(String args) Scanner keyboard new Scanner(System.in); int u 14; int w 0; int x; int y 5; float z = 6.1 System.out.print("Enter y: "); x keyboard.nextint); System.out.println('y'); System.out.println(x); System.out.println(w*3); x- x+(int)z; System.out.println(x); 0 System.out.println(u); System.out.,println(u); System.out.println"x In" + y); System.out.print(y + z); ) liclosing main method 1 liclosing class header
class Test public static void main(String args) { Aa=new AO: a.printo: class A private String s; public A (String news) { 8 = news: public void print { System.out.println(s): The program would compile and run if you change A a new Alto Aa=new A('5'). The program has a compilation error because the instance variables in class A is not public. The program has a compilation error because class A does not have a no-arguments constructor The program compiles and runs...