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Problem 32.52 Part A Complete the following fission reaction: 2n+235 U88Sr + 136 Xe +(?) neutrons Express your answer as an i

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Answer #1

given

mass of Neutron= 1.00866 amu

mass of Uranium = 235.04392 amu.

mass of Strontium = 87.90561 amu

mass of Xenon = 135.90721 amu

E= Δmc² ={ (mu + mn)-(mxe +msr+12n)}c2

(235.04392+1.00866)- (135.90721 + 87.90561+12*1.00866) c2 = 0.13581 *(2.99*10⁸ )²/1.6*10⁻¹⁹ eV

E =126.53496 MeV

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