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1. + -/21 points DevoreStat9 3.E.052. y Notes Suppose that 30% of all students who have to buy a text for a particular course

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Answer #1

a)

here this is binomial with parameter n=15 and p=0.3
mean of distribution=μ=np= 4.50
standard deviation σ=√(np(1-p))= 1.77

b)

2 standard deviation from mean values are μ -/+ 2*σ=(0.95,8.05)
probability = 1-P(1<=X<=8)= 1-∑x=x1x2     (nCx)px(1−p)(n-x)    = 1-0.9800=0.0200

c)

probability = P(5<=X<=10)= x=x1x2     (nCx)px(1−p)(n-x)    = 0.4838

d)

expected value =4.5*120+10.5*90 =1485

+ b) = a · E(X) + b E(aX

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