The C++ function to check whether the given tree is Binary Search Tree is as follows:
bool isBST(struct node* root)
{
static struct node *prev = NULL;
// traverse the tree in inorder fashion and keep
track of the previous node
if (root)
{
if (!isBST(root->left))
return
false;
// Allows only distinct valued
nodes
if (prev != NULL &&
root->data <= prev->data)
return
false;
prev = root;
return
isBST(root->right);
}
return true;
}
Code to copy:
// ConsoleApplication28.cpp : Defines the entry point for the
console application.
//
#include "stdafx.h"
#include<iostream>
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
using namespace std;
/* A binary tree node has data, pointer to left child
and a pointer to right child */
struct node
{
int data;
struct node* left;
struct node* right;
};
bool isBST(struct node* root)
{
static struct node *prev = NULL;
// traverse the tree in inorder fashion and keep
track of the previous node
if (root)
{
if (!isBST(root->left))
return
false;
// Allows only distinct valued
nodes
if (prev != NULL &&
root->data <= prev->data)
return
false;
prev = root;
return
isBST(root->right);
}
return true;
}
/*This function allocates a new node with the
given data and NULL left and right pointers. */
struct node* newNode(int data)
{
struct node* node = (struct node*)malloc(sizeof(struct
node));
node->data = data;
node->left = NULL;
node->right = NULL;
return(node);
}
/* Driver program to test above functions*/
int main()
{
struct node *root = newNode(7);
root->left = newNode(5);
root->right = newNode(10);
root->left->left = newNode(1);
root->left->right = newNode(6);
root->right->left = newNode(9);
root->right->right = newNode(8);
if (isBST(root))
cout<<"The given tree is a
BST";
else
cout<<"The given tree is not
a BST";
getchar();
return 0;
}
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