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The acid dissociation constant K, of alloxanic acid (HC H3N203) is 2.24 x 10^?. Calculate the pH of a 6.8 M solution of allox
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Answer #1

P Phas-logka Erlog (2.24x157) = 6.65 = pka - I lose = X6*65- I log (618) 23:325 - 120.832 - 30325 0.416 = 2.909 WI F S S 1 2Ans is 2.9

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