Question

n-1 tan .X n-2 Stanxdx ſtan xdx n-1

Can someone please explain how the middle expression ' tan^n-1x/n-1 ' is split?

The entire right-hand side then becomes ' Int tan^n-2 x tan^2xdx '

I'm just not sure what principles/methods I'm using to split this?

Thank you

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Answer #1

We know that tañx= 8ea1 tan a na e seca - 1] dx 1 2 ] de tan a beca = tana=t S tan he dx stanha do tan rã dir =/tan Spiteri b

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