Homework Answers
2HOCl -----> H2O + Cl2O , Kc = 0.0900
OR
H2O + Cl2O -----> 2HOCl , Kc' = 1/0.09 = 11.11
0.98 0.98 0 (at t = 0)
0.98-x 0.98-x 2x (at equilibrium)
Kc' = [HOCl]^2 / [H2O][Cl2O]
11.11 = (2x)^2 / (0.98-x)(0.98-x)
11.11 = (2x / 0.98 - x)^2
2x / 0.98 - x = 3.333
2x = 3.266 - 3.333x
5.333x = 3.266
x = 0.6125
At equilibrium;
[HOCl] = 2x = 2*0.6125 = 1.225 M .....Answer
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