Question

Yes, as it is in the mint abs. NO: 24,46 so 50 is an outlier (g) Find a 95% confidence interval for the slope. Interpret your confidence interval. (h) Test the null hypothesis that the slope is zero and describe your conclusion. (i) Suppose we wish to predict the mean per capita retail sale for the years with per capita personal income 16000. What is the 95% confidence interval for this prediction? 6) If the per capita personal income in 1984 is 16000, what is the 95% interval for the prediction of 1984's per capita retail sale? (k) What is the value of SST, the total sum of squares?

Answer 1

2 3 9 from the above tables, b, c 0.27767 and wh 35(61) = 0.04852 , df ofessor ofe) = 49° The 95%. cL for the slope B loisa evitaretta *+,-0.05 49 SECO) = 0.27760472.312 4*0.04852 =0,27167 + 0.11220 = (0.16547, 0.38987) HAC The 95% ca of slope include the population paramites i OB within the interval. 10.16547, 0.38987) with 95% confidence t Nitomata o t, inestogutt E) = suu-9 wcsstop them Test states trend t = 5.72 and corresponding p-value = 0.000 f from the above table). Here, the p-valen is less than 0.05. Hence, we reject the null hypothesis and conclude that the independent variable pesine has significant effect on the dependent variable retsal. e) The predicted mean per capita retail sale for the year with pes capital personal income 1600 is Y copo = 9127 +0,278x16000= 2577.8 6575 The confidence interval in 91000074oos, un rense) fist ber 05 | ISS n = Zbr-2} a =perine. = 651451 2.3134/403295(+ (6000-x)? from the geven information, the values of n and ssx can't find, o SSN Sp

3) Similar to i), the 95%. prediction internal when x=16000 Also tak, mse) (v * * the 334) = 6575 22.3124|403225( 145 + (5000-1) k) from Amoria table, ssta 32961271 1) The value of F = 32.74 .les, the square oft statistic for the slope hypothesis equal the for statistic The dy of msE=49 - SSA - n The value of mse = 403225 .