Interactive LearningWare 20.1 provides background for this problem. t in the 2.0-Ω resistor in the drawing
Interactive LearningWare 20.1 provides background for this
problem. 
t in the 2.0-Ω resistor in the
drawing
Homework Answers
Use 2 loops to solve this equation.. Top loop and bottom loop
Concider current in top i1 and current in the bottom i2.. Direction clockwise.
Top loop equation: i1 - 1 + 2i1 - 2i2 = 0
bottom equation: 4 + 3 i2 + 2i2 - 2i1 + 1 =0
simplify and solve bothe quations..
top: 3i1 - 2i2 = 1
bot: 5i2 - 2i1 = -5
i1 = -0.45A
i2 = - 1.18 A..
since they are negative that means they are
i1 = 0.45 A counter clockwise and
i2 = 1.18 counter clockwise..
To find the current in the R2.. you have to subtract both currents and the larger one takes the sign
0.45 - 1.18 = current in the R2
Current in R2 = 0.73 Amps coutner clockwise.
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Interactive LearningWare 20.1 provides background for this
problem. t in the 2.0-Ω resistor in the
drawing
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