Question

Mitomobile Cost continere with the average cost sowat $367 per react Assume that the cost to (a) What the probably that the cost wi t h yo u r (b) What is the probability that will be less than $2202 (Round you to our data (6) What is the probability that the cost will be between $750 and 54007 Ground your answer to your doomal oloom) 330 X $200 x

Answer 1

@ P(x > 480 ) = A = pl X-4 X 480-3677 Lot 88 =P(Z > 128) Our brist 1- P(Z <1-28) - 0.9004Z JP(x>480) = 0.ogg 6 l a do the cost will be more than $480 is probability that 0.0996

C 220-3677 6 P(X 2220) =P [X-4 88 =PL z < -147 - due to symmetry - = P(z L - 1.67) =plz > 1.67) on - 1-PCZE 1-67) = -0.9526 = 0.0474 TP ( X <220) probability that the cost will be less than $220 is 0.0474 p(2204 X <480) = /220-367 cx-u4 2 480-3677 L 98 88 Tell za 21.a = = 8(-1.67 L z < 1.28) - Plz6 1.28 ) - P(Z -1.67) = P( Z C 1.28) - P (z>1.67) IP(Z < 1:28) - Ii- Plz41.67)] = P(Z < 1.28) + P( ZL1.67) - = o goo4 +0.9526-1 P (220 LX c480) = 0.8530 probability that the cost will be between $220 and $420 is 0.8530

(d) P(xca) = 0.05 P[ X-ca-7-005 Plze a - 3677 -0.05 -0 " - from normal prob table P(Z <.1.645 ) = 0.05 from egn. 4 9-367 =-1-645 Q-367 9-367 -1645 788) - - 144.76 a = 222.24 the for lower maximam possible cost $222.24 St. is