Question

A home in Florida loses electricity when a hurricane makes landfall. The hurricane is slow- moving and takes several days to move through the area. In order to power a fan and a refrigerator, the homeowner starts a generator in his garage, which has a length of 6 m, a width of 5.5 m, and a floor-to-ceiling height of 2.5 m. The garage door is closed due to the hurricane and the ventilation rate is 0.60 air changes per hour (ach). The homeowner starts the generator, which releases an average of 990 g carbon monoxide (CO) per hour. The initial CO concentration in and around the garage is assumed to be zero, and no CO-based reaction takes place (i.e., the removal reaction rate constant is assumed to be zero). Molecular weights: C = 12; 0 = 16. a) What will be the steady-state CO concentration in the garage (g/m3)? b) How long (min) will it take until the garage concentration of CO reaches 12,800 ppm, a CO concentration that can result in death within three minutes of exposure? Assume the temperature in the garage is 30 °C (303.15 K) and the pressure is 1 atm. R = 8.2057*10-5 m3-atm/K-mol.

Answer 1

2. 
   Also where x(t) = concentration of gas after it time = 12 800 ppm - 12800 g/m2 -0.6x990 Rart - e 12800 = 990 (1125.6 0.6x990 le Fiat 0.6827 7.25 0.9173 t = 0.01198 hr Ita 0.719 min
   
   Also al volume of the room a 6x5.5x2.5 = 82.5m² Sout = 0.60 / x990 g - 5948/ur when Sin = 990 g cour molut of c=12, 0= 16 2 Mol lot of co= 28 Steady State co concentration in garage = 990 2x domex October - 209/03 To reach 12, 800ppm of co Concentration We know that Pr= nRT. (1)(82,5) = n(8.2057x16 x 303.15 n = 3316.505 mol no of moles - wt of Substance Molist of substance 3316.505 = wt of substance 16 .. wt of co- Density of co - 92862.150 g May volume = 1125.6 8