Volume of the object required to coat
= surface area thickness
= 61.5 (cm2) 5.9310-3 (cm)
= 0.365 cm3
Mass of Ni deposited
= volume of the object required to coat density of Ni
= 0.365 (cm3) 8.91(g/cm3)
= 3.25 g.
By Faraday law of electrolysis
W =
charge of Ni ( n factor) = +2
E is gm equivalent of Ni = ( atomic mass/ n factor) = (58.7/2)
= 29.35 g
W is mass of Ni deposited
= 3.25 g
i is current = 8.03 A
F = 96500 C
t is time in sec .
so, time required (t) to coat the object
t =
t = ( 3.2596500/ 8.0329.35)
t = 1331 s .
80.1% Resources Hint An object with a surface area of 61.5 cm is to be plated...
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