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80.1% Resources Hint An object with a surface area of 61.5 cm is to be plated with nickel. A current of 8.03 A is applied to
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Answer #1

Volume of the object required to coat

= surface area \small \times thickness

= 61.5 (cm2) \small \times 5.93\small \times10-3 (cm)

= 0.365 cm3

Mass of Ni deposited

= volume of the object required to coat  \small \timesdensity of Ni

= 0.365 (cm3)  \small \times 8.91(g/cm3)

= 3.25 g.

By Faraday law of electrolysis

W = Exixt

charge of Ni ( n factor) = +2

E is gm equivalent of Ni = ( atomic mass/ n factor) = (58.7/2)

= 29.35 g

W is mass of Ni deposited

= 3.25 g

i is current = 8.03 A

F = 96500 C

t is time in sec .

so, time required (t) to coat the object

t = W XF iXE

t = ( 3.25\small \times96500/ 8.03\small \times29.35)

t = 1331 s .

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