Question

The balanced combustion reaction for C, H, is 2C, H.(1) + 150,(e) 1200,(g) + 6H,0(1) +6542 kJ If 8.300 g C, H, is burned and the heat produced from the burning is added to 5691 g of water at 21 °C, what is the final temperature of the water? final temperature:

Answer 1

I have solved the question with a detail explanation. Just go through it to get all the conceptual ideas.
i. & 26 H6 (l) +15 0(g) 1200 (g) + IP 6 H₂0 (1) +6542 ki So g moles of benzene on combust. eon preoduces 6542 ks of heat. so here 8.3gm of benzene - 8.3 mole = 0,106 moles of benzene breaduces heat of (molare mass of benzene). 78 dass 6542 x 1000 x 0.106 = 346,726 j of energ

This o heat is added to 5691 gm of potere at 21°C as we know heat capacity of watere le the amount of head requireed to increase the tempreeturce of 1 gm of watere by 1 c is 4.18 Joule So for 5691 gm of substance, to in creease the rempraturce by 1 c, heat reequired = 4,1885691 = 23,788 Joule so 23 788) will increease the tempere- aturce of geven watere by 1°C. the increase So 346,726 j will cause of tempereature ³1 x 346,726 23,788 og = 14.57°C. So final temperature of watero will be a 21+ 14:57 = 35.57c.