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What is the percent yield of KOH when 22.4 grams of KO react with an excess of water to produce 13.9 grams of KOH? 4 KO () +
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Answer #1

moles MW = 0. 315 mol = 5 4K0265) + 2H2011) LKOHCS) +30219) a molee of koz= may. 22.42 ना.१०॥ - As pa creaction. 4 mole KO₂ p

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