Question

A 10.5 LL balloon contains helium gas at a pressure of 620 mmHgmmHg . What is the final pressure, in millimeters of mercury, of the helium gas at each of the following volumes, if there is no change in temperature and amount of gas?

answer the following questions with the above information, P3= mmHG

1.) 23.0 L

2.) 2.20 L

3.) 13700 mL

4.) 1210 mL

Answer 1

Using Piv, = PVL P= 620 mm Hg Vi= 10.5L o x 10, 23 Bo Pins690x10.5 283 mmity Đ Py = 620x10.5 = 2959 mming P = 15900 x 10 620X10.5 = 5380 mmHg 2.2 620 x 10.5 I 13700X10 3 = 475 mm Ho © R 1210x 10-3