Answer: Kp = 1/p[CO2]
explanation:
we write the equillbria-
CaO(s) + CO2(g) <=====> CaCO3 (s),
Let us consider,
p[CaO] = partial pressure of CaO
p[CO2] = partial pressure of CO2.
p[CaCO3] = partial pressure of CaCO3.
Then pressure equillbirium constant expression ,Kp can be written as:
Kp = p[CaO(s)]*p[CO2(g)]/p[CaCO3 (s)]
Since , activities of solids and liquids are unity ,and then the partial pressure should also be omitted from above expression, therefore,
Kp = 1/[CO2 (g)]
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