Question

A certain reaction has an activation energy of 53.55 kJ/mol. At what Kelvin temperature will the reaction proceed 7.50 times faster than it did at 315 K?

Answer 1

Ki The activation energy (Ea) = 53.65 kJ/mol . Let the rate constant be ki at 315k now for reaction to proceeds 7.50 faster then the rate constant will be Kz and ratio of rate constant & K₂ = 7.50 According to Arrhenius equation : In ( k ) = ea co lt I) i R= gas constant nowe, dom (19) Sosyx og planten als - ) 3.122 x 1004 - guts ç - 28.624x164K" = T2 = 22.622x10-4 = 349.35 K The final temperature of the reaction is .349k. 31 Scanned with CamScanner