Pure solids such as CaCO3 and CaO in this case are not written in the expressions of equilibrium constants.
Problem 2 (10 points). For the following heterogeneous equilibrium at 800°C: CaCO3(s) ở CaO(8) + CO2(g)...
CaCO3(s) ⇄ CaO(s) + CO2(g) 0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K. When equilibrium is reached the pressure of CO2 is 0.220 atm. 0.300 atm of CO2 is added, while keeping the temperature constant and the system is allowed to reach again equilibrium. What will be the final mass of CaCO3? 7.47 g 12.54 g 18.01 g 2.00 g 10.01 g
CaCO3 (s) ⇌ CaO (s) + CO2 (g) At 658 °C, the reaction reaches equilibrium. If PCO2 =2.17 atm, what is Kc value ?
CaCO3 (s) ⇌ CaO (s) + CO2 (g) At 637 °C, the reaction reaches equilibrium. If PCO2 =0.89 atm, what is Kc value ?
1) 2) 3) CaCO3(s) = CaO (s) + CO2 (g) At 658 °C, the reaction reaches equilibrium. If PcO2 =2.17 atm, what is Kc value ? *Please report 3 significant figures. Numbers only, No unit. No scientific notation. The slope and intercept of an Arrhenius plot made for the first-order decomposition reaction are -7865.2 K and 26.098 at 303K, what is the value of the activation energy (KJ/mol) at this temperature? *Please report 3 significant figures. Numbers only, no unit....
Consider the heterogeneous equilibrium process: C(s) + CO2(g) ⇆ 2CO(g) At 700°C, the total pressure of the system is found to be 1.50 atm. If the equilibrium constant (KP) is 1.52, calculate the equilibrium partial pressures of CO and CO2.
CaCO3(s) = Cao (s)+CO2 (g) When heated strongly, solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxide gas, as represented by the equation above. A 2.0 mol sample of CaCO3(s) is placed in a rigid 100. L reaction vessel from which all the air has been evacuated. The vessel is heated to 898°C at which time the pressure of CO2(g) in the vessel is constant at 1.00 atm, while some CaCO3(s) remains in the vessel. a. Calculate...
For the endothermic reaction CaCO3 (s) <-----> CaO (s) + CO2 (g) Le Chtelier's principle predicts that __________ will result in an increase in the number of moles of CO2 at equilibrium. a. increasing the temperature b. decreasing the temperature c. increasing the pressure d. removing some of the CaCO3(s) e. adding more CaCO3 (s)
Consider the reaction: CaCO3(s)⇌CaO(s)+CO2(g) An equilibrium mixture of this reaction at a certain temperature was found to have [CO2]= 0.458 M. What is the value of the equilibrium constant at this temperature?
QUESTION 1 CaCO3(s) = Cao (s) + CO2(g) At 788 °C, the reaction reaches equilibrium. If PC02 -1.97 atm, what is Kc value ? *Please report 3 significant figures. Numbers only, No unit. No scientific notation.
At 900 °C, K = 0.0108 for the reaction CaCO3(8) F CaO(s) + CO2(g) A mixture of CaCO3, CaO, and CO2 is placed in a 10.0-L vessel at 900 °C. For the following mixtures, will the amount of CaCO3 increase, decrease, or remain the same as the system approaches equilibrium? Part A 15.0 g CaCO3, 15.0 g CaO, and 4.25g CO2 increases decreases O remains the same Submit Request Answer Part B 2.50g CaCO3, 25.0 g CaO, and 5.66 g...