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b. When 12.00 mL of 0.183 M BaCl2 were mixed with 10.00 mL of 0.352 M...
Please help!! with question (18 ,19, 20 ) the data is coming directly from professor and...
Please help!! with question (18
,19, 20 )
the data is coming directly from
professor and i think she made a mistake because after I work out
problem I get theoritcal yeild of 0.850 grams
CaCO3 but the experiment actual yield is 8.322 grams (work out
question 12 )
Carbonate LI General Chemistry Lab I H.Y. & S.D. ame ata Sheet Section Date • Precipitating Cacos 1) Volume of Na2CO3, mL 8.22mL or 0.00824 2) Molarity of Na2CO3 solution, mol/L...
when 15.67 ml of 0.250 M NaCl is mixed with 23.11 ml of 0.187M Ba(NO3)2 a...
when 15.67 ml of 0.250 M NaCl is mixed with 23.11 ml of 0.187M
Ba(NO3)2 a precipitation reaction occurs according to the reaction
equation below. this reaction was carried out and 0.351 g og BaCl2
was recovered.
determine the following:
a. limiting reagent
b. theoretical yield (BaCl2)
c. % yield
ed with 23.11 mlot according to 63. When 15.67 ml of 0.250 M NaCl is mixed with 0.187 M Ba(NO3), a precipitation reaction or the reaction equation below. This reaction...
A 1.00 mL solution containing 0.400g BaCl2-2H20 is mixed with 50.00 mL of a solution containing...
A 1.00 mL solution containing 0.400g BaCl2-2H20 is mixed with 50.00 mL of a solution containing 0.300 g NalO3. Determine the mass of Ba(IO3)2 formed. Ksp(Ba(IO3)2) = 1.6x10-9 Determine the saturation state of seawater (n) for calcite at pH 8.10 (current) and pH 7.80 (year 2100). The concentration of calcium is constant at 0.0103 M. The concentration of carbonate is 2.40x10- M (pH 8.10) and 1.48*10M (pH 7.8) Ksp (calcite) 4.272x10-7
A 1.00 mL solution containing 0.400g BaCl2:2H2O is mixed with 50.00 mL of a solution containing...
A 1.00 mL solution containing 0.400g BaCl2:2H2O is mixed with 50.00 mL of a solution containing 0.300 g NalO3. Determine the mass of Ba(103)2 formed. Ksp (Ba(103)2) = 1.6x10-9 Determine the saturation state of seawater (12) for calcite at pH 8.10 (current) and pH 7.80 (year 2100). The concentration of calcium is constant at 0.0103 M. The concentration of carbonate is 2.40x10-4M (pH 8.10) and 1.48x10-4M (pH 7.8). Ksp*(calcite) = 4.272x10-7 Calculate the activity coefficient of K+ in a 0.0500...
I just need help understanding the steps to get the theoretical yeild and percent yield of...
I just need help understanding the steps to get the
theoretical yeild and percent yield of CaCO3. using the given
information.
H.Y. & S. D. Precipitating Calcium Carbonate CHMI21 General Chemistry Lab 1 • Treatment of Data: 14) mole amount of Na CO, 15) mole amount of CaCl 16) limiting reagent .00832 00976 NonCO₃ .00735 .832 .au 112.98 mole amount of CaCO, 17) 18) 19) 20) Theoretical Yield (g) of Cacos Actual Yield (g) of Caco, Percent Yield (%) Calculations...
25.67 mL of 4.786 M iron (III) chloride solution reacted with 26.57 mL of 5.376 M...
25.67 mL of 4.786 M iron (III) chloride solution reacted with
26.57 mL of 5.376 M ammonium carbonate producing iron (III)
carbonate as precipitate at 89.58%
write proper annotated balanced chemical reactions. need help
understanding each step using the ICE method.
To facilitate calculations here molar masses of involved elements to be used: 26.982 74.922 137.327 79.904 Aluminum g/mol Arsenic g/mol Barium g/mol Bromine g/mol 40.078 12.011 35.453 1.008 Calcium g/mol Carbon g/mol Chlorine g/mol Hydrogen g/mol 55.845 207.2 Iron...
EXPERIMENT 9 CHEMICAL REACTIONS: STOICHIOMETRY LABORATORY REPORT Your Name TA's Name You must rea...
EXPERIMENT 9 CHEMICAL REACTIONS: STOICHIOMETRY LABORATORY REPORT Your Name TA's Name You must read pages 69 and 70 to complete the following calculations. Lab Section 1411. Date Trial #1 Trial #2 Trial #3 vol . 0.100 M K2CO, solution -1200 mL 12.00 mL mmole K2CrO vol. 0.100 M Pb(NO,), solution 10.00ml mmole Pb(NO) 12.00m 14.00 mL 20 g mass product+paper 0.579 g0.654 g mass dry filter paper 0266 mass PbCrO, collected precip. 9 mmole Pbcro, CALCULATIONS AND QUESTIONS (USE THE...
Please help!! with question (18
,19, 20 )
the data is coming directly from
professor and i think she made a mistake because after I work out
problem I get theoritcal yeild of 0.850 grams
CaCO3 but the experiment actual yield is 8.322 grams (work out
question 12 )
Carbonate LI General Chemistry Lab I H.Y. & S.D. ame ata Sheet Section Date • Precipitating Cacos 1) Volume of Na2CO3, mL 8.22mL or 0.00824 2) Molarity of Na2CO3 solution, mol/L...
when 15.67 ml of 0.250 M NaCl is mixed with 23.11 ml of 0.187M
Ba(NO3)2 a precipitation reaction occurs according to the reaction
equation below. this reaction was carried out and 0.351 g og BaCl2
was recovered.
determine the following:
a. limiting reagent
b. theoretical yield (BaCl2)
c. % yield
ed with 23.11 mlot according to 63. When 15.67 ml of 0.250 M NaCl is mixed with 0.187 M Ba(NO3), a precipitation reaction or the reaction equation below. This reaction...
A 1.00 mL solution containing 0.400g BaCl2-2H20 is mixed with 50.00 mL of a solution containing 0.300 g NalO3. Determine the mass of Ba(IO3)2 formed. Ksp(Ba(IO3)2) = 1.6x10-9 Determine the saturation state of seawater (n) for calcite at pH 8.10 (current) and pH 7.80 (year 2100). The concentration of calcium is constant at 0.0103 M. The concentration of carbonate is 2.40x10- M (pH 8.10) and 1.48*10M (pH 7.8) Ksp (calcite) 4.272x10-7
A 1.00 mL solution containing 0.400g BaCl2:2H2O is mixed with 50.00 mL of a solution containing 0.300 g NalO3. Determine the mass of Ba(103)2 formed. Ksp (Ba(103)2) = 1.6x10-9 Determine the saturation state of seawater (12) for calcite at pH 8.10 (current) and pH 7.80 (year 2100). The concentration of calcium is constant at 0.0103 M. The concentration of carbonate is 2.40x10-4M (pH 8.10) and 1.48x10-4M (pH 7.8). Ksp*(calcite) = 4.272x10-7 Calculate the activity coefficient of K+ in a 0.0500...
I just need help understanding the steps to get the
theoretical yeild and percent yield of CaCO3. using the given
information.
H.Y. & S. D. Precipitating Calcium Carbonate CHMI21 General Chemistry Lab 1 • Treatment of Data: 14) mole amount of Na CO, 15) mole amount of CaCl 16) limiting reagent .00832 00976 NonCO₃ .00735 .832 .au 112.98 mole amount of CaCO, 17) 18) 19) 20) Theoretical Yield (g) of Cacos Actual Yield (g) of Caco, Percent Yield (%) Calculations...
25.67 mL of 4.786 M iron (III) chloride solution reacted with
26.57 mL of 5.376 M ammonium carbonate producing iron (III)
carbonate as precipitate at 89.58%
write proper annotated balanced chemical reactions. need help
understanding each step using the ICE method.
To facilitate calculations here molar masses of involved elements to be used: 26.982 74.922 137.327 79.904 Aluminum g/mol Arsenic g/mol Barium g/mol Bromine g/mol 40.078 12.011 35.453 1.008 Calcium g/mol Carbon g/mol Chlorine g/mol Hydrogen g/mol 55.845 207.2 Iron...
EXPERIMENT 9 CHEMICAL REACTIONS: STOICHIOMETRY LABORATORY REPORT Your Name TA's Name You must read pages 69 and 70 to complete the following calculations. Lab Section 1411. Date Trial #1 Trial #2 Trial #3 vol . 0.100 M K2CO, solution -1200 mL 12.00 mL mmole K2CrO vol. 0.100 M Pb(NO,), solution 10.00ml mmole Pb(NO) 12.00m 14.00 mL 20 g mass product+paper 0.579 g0.654 g mass dry filter paper 0266 mass PbCrO, collected precip. 9 mmole Pbcro, CALCULATIONS AND QUESTIONS (USE THE...
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