Question

ZI 5-0 2. Estimate the pl value of the following pentapeptide. Explain. (5 marks) H2N-CHC N-CHC N-CHC-OH CH2 CH3 CHOH CHCH3 C

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Answer #1

0 -HN-CH- E chte N-CH-i ich-i N-CH-Ion TE . ch - arch On Ch crk With At pkg = 2:29 nel charge : +1. -&-N-CH-8 _-Ç--&-NH-cu- &

At p​​​​​​k1​​​​ = 2.29 the net charge is 1

At p​​​​​​k2​ = 9.12 the net charge is 0

Here zwitter ion is formed.

So isoelectric point is pI =( 2.29+9.12)/2 = 5.70

So the pI value of the given peptide chain is 5.70

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