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Determine the voltage (V) of the following cell at 25°C: Zn(s) | Zn2+(aq, 0.37 M) || Cl-laq, 0.75 M) C12(g, 0.750 atm)| Pt St
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Answer #1

Zn(s) ---------------> Zn^2+(aq) + 2e^-           E0 = 0.76v

Cl2(g) + 2e^- ------------> 2Cl^- (aq)             E0 = 1.36v

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Zn(s) + Cl2(g) --------> Zn^2+(aq) + 2Cl^-(aq)     E0cell = 2.12v

n = 2

Ecell   = E0cell -0.0592/nlogQ

         = 2.12-0.0592/2 log[Zn^2+][Cl^-]^2/PCl2

        = 2.12-0.0296log0.37*(0.37)^2/0.75

       = 2.12-0.0296log0.06754

         = 2.12-0.0296*-1.1704

        = 2.155v >>>>answer

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