Zn(s) ---------------> Zn^2+(aq) + 2e^- E0 = 0.76v
Cl2(g) + 2e^- ------------> 2Cl^- (aq) E0 = 1.36v
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Zn(s) + Cl2(g) --------> Zn^2+(aq) + 2Cl^-(aq) E0cell = 2.12v
n = 2
Ecell = E0cell -0.0592/nlogQ
= 2.12-0.0592/2 log[Zn^2+][Cl^-]^2/PCl2
= 2.12-0.0296log0.37*(0.37)^2/0.75
= 2.12-0.0296log0.06754
= 2.12-0.0296*-1.1704
= 2.155v >>>>answer
this is the complete question (no more info) Determine the voltage (V) of the following cell...
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