Question

Question 13 when 12.259g of a compound containing only copper and oxygen was decomposed it produced 2.410g of oxygen. how many grams of cooper were in the compound ? part b: a second compound in question 13 above released 1.734g of oxygen when it was decomposed. how many many grams of copper were in this second sample(use the information in question 13 too). part c: taking the same compound of question 13,how many grams of the compound would be required to produce 3.082g of oxygen?

Answer 1

(③ past (a) Decomposition, Compound Copper + Oxygen (contain copper and oxygen) 13-2599 2:410g According to Law of Conservation of mass, mass in a closed system is neither created nor destroyed by chemical reactions. The mass of the products in a chemical reaction must equal to the mass of the reactants. mass of Compound = mass of copper t mass of oxygen 12.259 g = mass 8 copper t 2.4109 Mass of copper - 12.259 g - 2.4109 Mass of copper = 9.849 g Part (6) from part (9) Decomposition, Compound Copper + Oxygen (contain copper and oxygen) 12:259 g 9.8499 2.4109 mass of copper when 2.410g Oxygen produced = 9.8499 mass of copper when 1:0 9 Oxygen produced = 9.849 g 2,410 mass of copper when 1.7349 Oxygen poroduced = 9.849 g x 1.734 2.410 - 7.086 g Unitary method is used Complete decomposition of compound is considered. Law of conservation of mass is used ☺ Part (c) from part a Decomposition, Compound Copper + Oxygen (Contain copper and oxygen) (२-२६११ 9.8499 2.4109 mass of compound when 2.4109 Oxygen produced = 12-259 g mass of compound when log Oxygen produced = 12-259 g 2.410 mass of compound when 3.082 g Oxygen produced = 12.259 g x 3-082 2.410 - 15.6779 Unitary method is used Complete decomposition of is considered compound o law of conservation of mass is used