Question

The molar solubility of nickel(II) carbonate in a 0.170 M sodium carbonate solution is M. Submit Answer Try Another Version 3 item attempts remaining

Answer 1

The reaction for the dissociation of nickel carbonate is as follows:

Let s be the solubility.

NiCO3(s) <----> Ni^2+(aq) + CO3^2-(aq)

s s

For, sodium carbonate :

Na2CO3 <-----> 2Na^+ + CO3^2-

2*0.170 0.170

Solubility product for NiCO3 is  Ksp = 6.6*10^-9

Then, Ksp = s*(s+0.170)

s is much less than 0.170 so, s + 0.170 = 0.170

6.6*10^-9 = s * 0.170

s = 3.88*10^-8

Therefore, solubility of NiCO3 = 3.88*10^-8 M.

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