Question

Quantized and total photon energy The particle characteristics of electromagnetic radiation are responsible for the quantized behavior of light energy. This behavior explains the results of varying the intensity and wavelength for an observed photoelectric effect, which describes the emission of electrons when light shines on a metal surface. If light only exhibited a purely wavelike behavior, then either increasing the intensity or decreasing the wavelength would both increase the rate at which electron are emitted. However, monochromatic light of longer wavelengths does not cause electrons to be emitted because no single photon within that range contains enough energy to cause the emission of an electron. The energy of a photon can be described by the following equation: E = hv = hc where E is energy in J), h is the Planck constant (6.626 x 10-34 J·s), and c is the speed of light (3.00 x 10 m/s). For photons that are traveling in phase, which means their frequencies are the same or multiples of each other, they produce a rather uniform wave with increased amplitude. The amplitude of a wave increases in squared proportion to the number of photons (e.g., if the number of in-phase protons doubles, the amplitude will quadruple). This describes the wave behavior for a beam of light In reality, most light is made up of photons of various wavelengths that are not in phase (which, in general, is called interference), thus the average rate of energy is measured instead of determining the amplitude at a specific point. A watt is the number of joules per second, which describes the average rate of energy a beam of light can deliver to a surface. To observe the more chaotic nature of a light wave, you can select the Manual or Oscillate radio button in the simulation as well as Fixed End or Loose End, then randomize the interval of times in which you generate a pulse while varying its amplitude (how far the pulse travels vertically) and width (a quick movement for smaller width or a slow movement for larger width). In a short amount of time (within 10 to 20 "shakes" or pulses), you will be able to observe an overall wave with various amplitudes that change over time.

Answer 1

Ang As given in the questions the frequency of photors, U= 7.5X10²42 In the passage it is discussed, how to calculete energy of a photon E ne - 10 C = hu E = 6-626X10-34% 7.54709 J E = 49.695 X10-25 J for 1 mol of photows, Energy - energy in Iphoton X NA = 49.695 x 10-21 x 6.0 22x102) = 299.96800 Energy = 2.997