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Experiment 4: Identification of an unknown acid by titration Page 2 of 15 Background In this experiment, you will use both quFor any titration, knowing the relationship between the moles of analyte in your titration sample and the moles of titrant usExperiment 4: Identification of an unknown acid by titration Page 4 of 15 A. Initial pH: Before any titrant is added, the majVisual titrations (with color indicators) To safely assume that the endpoint is an accurate representation of the equivalence[xperment 4. Toen TCATOn or an UNKTOWI OCIO O TILTALTON Tage os Identifying a weak acid The half-equivalence point is especiaHow does this calculation differ from your lab? The calculation on the previous page uses a known concentration and volume ofLet us summarize your findings related to this key question: How do acid concentration and K, affect titration curves? • To aQuestion 9 options: If the initial concentration of the weak acid HA was increased, the pH at half- equivalence would... IncrIt's a weak acid strong base titration

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Answer #1

1.) Decrease. This is so as the concentration of weak acid increases, it is more dissociated as per equilibrium Eq.

HA + H2O= H3O+ + A- (a)

Hence, Ka (pH at half equivalence) which is equal to [H3O+] [A-]/[HA] would increase which would decrease pKa value given by -log Ka.

2.) Increase. This is so as more Ka value means acid is stronger. More of H+ ions are being formed. Hence, to neutralize a stronger acid, more volume of NaOH will be required.

3.) Increase. Higher the concentration of weak acid, more of H+ ions are being generated as per Eq. (a). Hence, larger volume of NaOH will be required to neutralize the acid completely.

4.) Decrease. pH at half equivalence is pKa which is -log pKa. If value of Ka increases, pKa will decrease.

5.) Stay the same. pH at half equivalence is pKa which is dependent on the type of acid, its concentration and hence, concentration of H+ ions produced. It is the property of an acid. It is independent of the concentration of NaOH used.

6.) Decrease. Increasing NaOH concentration would require lesser volume of NaOH to neutralize the acid completely as for the same concentration of H+ ions, higher concentration of NaOH gives more OH- ions to neutralize at lower amount.

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