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Please help me find the value of -Ea/R from ln k' vs 1/T graph E. Determination of Activation Energy Time for color change Reaction rate Calc. K 1 Ink Temperature 1/T(K) 1. Trial 4 34 sec

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Answer #1

-13.5 0.0032 0.00325 0.0033 0.00335 0.0034 0.00345 0.0035 0.00355 0.0036 0.00365 -14 Ink y = -5435.x + 3.881

The trendline equation is y = -5435.x + 3.881

Comparing with Arrhenius equation :

lnK’ = lnA + (-Ea / RT)

slope =        -Ea/R = -5435 K

   this implies that Ea = 5435 x R

unit of slope is Kelvin and unit of R is JK-1

Ea = 5435 x 8.314 J = 45186.59 J = 45.18659 KJ

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