Question

7.27 20180528_Inova_500_isopropyl acetate-PROTON_01 5.03 5.02 5.01 66 OL84.974.98 4.96 Chemical Shift (ppm) 4.0 .......... 2.

6. (a)Complete the table: Signal Chemical shift, 8 (ppm) Splitting pattern (singlet, doublet, triplet, quartet, pentet. sixte

(b)How can you use 1H NMR to distinguish between isopropyl ethanoate and methyl 2-methylpropanoate.

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Answer #1

A)

Signal

Chemical Shift

Splitting pattern

No of H neighbours

Integration of protons

Circle or highlight the protons that give rise to signal

A

4.99

Septet

6

1

B

2.02

Singlet

0

3

C

1.24

doublet

1

6

B) To distinguish between isopropyl ethanoate and methyl 2-methylpropanoate, we can use H1 NMR

In case of Isopropyl ethanoate, there is only one hydrogen atom attached to carbon atom directly attached to oxygen atom thus there would be 1 H atom showing chemical shift between 4-5 ppm (splitting pattern- septet) whereas in case of methyl 2-methyl propanoate there would be three such hydrogen atoms attached to carbon atom directly attached to oxygen atom thus there would be 3 H atom showing chemical shift between 4-5 ppm (splitteing pattern- singlet). Thus with integration of protons we can easily distinguish between them

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