Question

An aqueous solution of calcium hydroxide is standardized by titration with a 0.190 M solution of hydrochloric acid. If 19.4 mL of base are required to neutralize 22.9 mL of the acid, what is the molarity of the calcium hydroxide solution? M calcium hydroxide Submit Answer Retry Entire Group 4 more group attempts remaining

Answer 1

1 The reaction involved in titration of Calcium hydroxide (Cacow)) with hydrochloric acid (HCl) is, Cacka & & HO (salt) Carohe & & Hd (Base) (Acid) (1 mde, (& moe) * Base (Carote) no. of ndes (n)= Imd volume (1) 19.4me olarity (Mi) = ? Aid CHO no. of ndes (ne) ² End volume (Ve) = 22.9 me molarity (Me) = 0-190m awe know that made me e bors - Move i mo X 19.4me Then, 0.190m x 22.9 ml & ma My = 0.11&m : Molarity of Glum hydroxide 0-11&M

- hydro Bromic acid The nutralisation reaction of (HBr) and Calottle is, + - & HBr (Acid) (& moer Ca(OH)e (Base) (1 mde) Cabre, + & HO salt) Acid (HBV) n, and = 88.7 me Mi = ? Base (Cacot),) nqz ind qz e9•& me Mę z 0.155m we know that mo m Mile 9y an - Male ) a Miz Mqų r ne Then, 0.155M X 29. & me & md 1 ma &8.7 me Mi = 0.315m · Molarity of hydro Biomic acid - 0.315m

U mass a Calciom Acetate (m)- 20.4 gr Molar mass of Calcium Acetate (CGC CH₂ (0)2] = 158g/ml Mont] volume of water (1) 185 me we know that molarity (M) = m x 1000 vlme) M.wt Then, M. &0.4 x 1000 m 198 125 M = 1.04M i Molarity of solution (M) = 1:04M) In solution, Carchisoode - Cath + & CH3COO molar Concentrations are loum 1.OUM & J•OUM - &:08M Concentration of calcium cation (Cath] = 1.0497 Concentration of acetate anion (CH3c00) = 2:08M/

mass of Chromium (11) Bromide (m) 19.8gr - Molarmass of cr Brer (M. Cut) = & 11.8 grloral volume of water (0) = 850 me we know that molarity (M) = m x 100 Then m (M)= 19.8 x 1000 &1118 850 M= 0.374 M . Molanity of solution 0.374m| lag In slution, crore → croq + & Braq molar concentrations are, 0.374 M 2x0.37UM -0.748M . Concentration of chromium (1) [crv] = 0.374M Concentration & Bromide (Br) 0.748M 0.37UM