Kb = 6.1*10^-5
pKb = - log (Kb)
= - log(6.1*10^-5)
= 4.215
use:
pOH = pKb + log {[conjugate acid]/[base]}
= 4.215+ log {0.44/0.25}
= 4.46
use:
PH = 14 - pOH
= 14 - 4.4602
= 9.5398
Answer: 9.54
If a buffer solution is 0.100 M in a weak base (Kb = 6.5 x 10-5) and 0.420 M in its conjugate acid, what is the pH? pH =
If a buffer solution is 0.270 M in a weak base (Kb = 4.7 x 10-5) and 0.480 M in its conjugate acid, what is the pH? - pH = L pH=
If a buffer solution is 0.240 M in a weak base (Kb = 8.9 × 10-5) and 0.420 M in its conjugate acid, what is the pH?
If a buffer solution is 0.220 M in a weak base (Kb = 8.1 × 10-5) and 0.540 M in its conjugate acid, what is the pH?
If a buffer solution is 0.290 M in a weak base (Kb = 7.3 × 10-5) and 0.470 M in its conjugate acid, what is the pH?
If a buffer solution is 0.170 M in a weak base (Kb = 8.5×10−5 M) and 0.480 M in its conjugate acid, what is the pH?
If a buffer solution is 0.210 M in a weak base (Kb = 4.9 × 10 − 5 M) and 0.480 M in its conjugate acid, what is the pH?
If a buffer solution is 0.280 M in a weak base (Kb = 4.0 x 10-5 ) and 0.430 M in its conjugate acid, what is the pH?
If a buffer solution is 0.220 M in a weak base (K) = 7.8 x 10 ) and 0.440 M in its conjugate acid, what is the pH?
If a buffer solution is 0.100 M in a weak base (Kb = 5.0 * 10%) and 0.490 M in its conjugate acid, what is the pH? Number pH = 18.6