Question

Be sure to answer all parts. A sample of air occupies 4.70 L when the pressure is 2.70 atm. (a) What volume does the sample occupy at 6.40 atm at the same temperature? L (b) What pressure is required in order to compress it to 0.0450 L at the same temperature? atm

Answer 1

PART (a):

Constant temperature.

Apply Boyle's law:

P₁V₁ = P₂V₂

∴ V₂ = (P₁V₁) / (P₂) = (2.7 * 4.7) / (6.4)

∴ V₂ = 1.98 L

• Volume at 6.40 atm = 1.98 L

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PART (b):

Constant temperature.

Hence, apply Boyle's law:

P₁V₁ = P₂V₂

∴ P₂ = (P₁V₁) / (V₂) = (2.7 * 4.7) / (0.0450)

∴ P₂ = 282 atm

• Pressure required to compress = 282 atm