Question

A 1.0 L buffer is made at 25 °C that consists of 0.80 mol of a...

A 1.0 L buffer is made at 25 °C that consists of 0.80 mol of a weak acid HA and 0.80 mol of its conjugate base A-. The acid ionization constant is Ka = 1·10-4.To this buffer solution 0.80 mol NaOH is added. Assuming that the volume change due to the added NaOH is negligible, calculate pOH-in the resulting solution.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Q. 0.80 mal Of weak Acid + 0.80 mal conjucate Base A- +0.80 mal Noon HAcaq) + OH Caq) —— Acaq) + H2068) dritial Oigo mal 0.8o

Add a comment
Know the answer?
Add Answer to:
A 1.0 L buffer is made at 25 °C that consists of 0.80 mol of a...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Part A: What is the pH of a buffer prepared by adding 0.708 mol of the...

    Part A: What is the pH of a buffer prepared by adding 0.708 mol of the weak acid HA to 0.406 mol of NaA in 2.00 L of solution? The dissociation constant Ka of HA is 5.66×10−7. Part B:What is the pH after 0.150 mol of HCl is added to the buffer from Part A? Assume no volume change on the addition of the acid. Part C: What is the pH after 0.195 mol of NaOH is added to the...

  • 12. Assuming no volume change, calculate the pH of: a. a solution made from 0.0500 mol...

    12. Assuming no volume change, calculate the pH of: a. a solution made from 0.0500 mol of NaOH(s) added to 1.00 L of pure water. → b. a solution made from 0.0500 mol of NaOH(s) added to 1.00 L of a buffer containing 0.100 mol each of weak acid (pK = 5.00) and its conjugate base.

  • A 1.32 L buffer solution consists of 0.121 M butanoic acid and 0.345 M sodium butanoate....

    A 1.32 L buffer solution consists of 0.121 M butanoic acid and 0.345 M sodium butanoate. Calculate the pH of the solution following the addition of 0.066 moles of NaOH. Assume that any contribution of the NaOH to the volume of the solution is negligible. The Ka of butanoic acid is 1.52 × 10-5. A 1.44 L buffer solution consists of 0.326 M propanoic acid and 0.103 M sodium propanoate. Calculate the pH of the solution following the addition of...

  • What is the pH of a buffer prepared by adding 0.506 mol of the weak acid HA to 0.305 mol of NaA in 2.00  L of solu...

    What is the pH of a buffer prepared by adding 0.506 mol of the weak acid HA to 0.305 mol of NaA in 2.00  L of solution? The dissociation constant Ka of HA is 5.66*10^-7. pH = __________ What is the \rm pH after 0.150 mol of \rm HCl is added to the buffer from Part A? Assume no volumechange on the addition of the acid. pH = _____________ What is the \rm pH after 0.195 mol of \rm NaOH...

  • A buffer solution with a volume of 0.0250 L consists of 0.61 M iodous acid (HIO2),...

    A buffer solution with a volume of 0.0250 L consists of 0.61 M iodous acid (HIO2), a weak acid, plus 0.61 M lithium iodite (LiIO2). The acid dissociation constant of iodous acid, Ka, is 3.2 ✕ 10−5. Determine the pH of the buffer solution after the addition of 0.0034 mol sodium hydroxide (NaOH), a strong base. (Assume no change in solution volume.) can u solve with an ice table? thank you.

  • Part A What is the pH of a buffer prepared by adding 0.506 mol of the weak acid HA to 0.608 mol of NaA in 2.00 L of so...

    Part A What is the pH of a buffer prepared by adding 0.506 mol of the weak acid HA to 0.608 mol of NaA in 2.00 L of solution? The dissociation constant Ka of HA is 5.66×10−7. Express the pH numerically to three decimal places. pH = SubmitHintsMy AnswersGive UpReview Part Part B What is the pH after 0.150 mol of HCl is added to the buffer from Part A? Assume no volume change on the addition of the acid....

  • In a preparation of a buffer, 1.0 L of weak acid solution of phenol HOC6H5 with...

    In a preparation of a buffer, 1.0 L of weak acid solution of phenol HOC6H5 with [M] = 0.85 M was mixed with its phenolic salt NaOC6H5 of [M] = 0.80 M. (Ka for HOC6H5 = 1.6 X 10-10) (i)Write equilibrium chemical equation for ionization of HOC6H5 ? (ii)Write equilibrium chemical equation for hydrolysis of the anion OC6H5 ? (iii)Calculate the pH of this solution using the Henderson-Hasselbalch equation? (iv)(a)Calculate the pH after 50 mL of 1.5 M HCl has...

  • Part A What is the pH of a buffer prepared by adding 0.708 mol of the weak acid HA to 0.406 mol of NaA in 2.00 Lof sol...

    Part A What is the pH of a buffer prepared by adding 0.708 mol of the weak acid HA to 0.406 mol of NaA in 2.00 Lof solution? The dissociation constant Ka of HA is 5.66×10−7. Express the pH numerically to three decimal places. Part B What is the pH after 0.150 mol of HCl is added to the buffer from Part A? Assume no volume change on the addition of the acid. Express the pH numerically to three decimal...

  • Question two A buffer solution is able to maintain a constant pH when small amounts of...

    Question two A buffer solution is able to maintain a constant pH when small amounts of acid or base are added to the buffer. Consider what happens when 1 mL of a 5 M solution is added or 0.005 mol of HCl are added to a 100.0 ml solution acetic acid buffer that contains 0.0100 mol of Acetic acid, HC,H,O,, and 0.0100 mol of sodium acetate, NaC,H,O2. The initial concentration of both the acid and the base are 0.0100 mol/0.1000...

  • What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka...

    What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.100 mol of NaOH were added?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT