Iodine is prepared both in the laboratory and commercially by adding Cl 2 ( g ) to an aqueous solution containing sodium iodide. 2 NaI ( aq ) + Cl 2 ( g ) ⟶ I 2 ( s ) + 2 NaCl ( aq ) How many grams of sodium iodide, NaI , must be used to produce 38.1 g of iodine, I 2 ?
According to the reaction,
1 mole I2 require 2 mole NaI
253.8 g I2 require 2×149.89 = 299.78 g NaI
38.1 g I2 require 299.78×38.1/253.8 g NaI
= 45.0 g NaI
Iodine is prepared both in the laboratory and commercially by adding Cl 2 ( g )...
Iodine is prepared both in the laboratory and
commercially by adding Cl, (g) to an aqueous solution containing
sodium iodide. 2 Nal(aq) + C1,(g) I, (s) + 2 NaCl(aq) How many
grams of sodium iodide. Nal, must be used to produce 91.4 g of
iodine. I2?
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