An analytical chemist is titrating 228.9 mL of a 0.6800 M solution of isopropylamine ((CH3)2CHNH2) with a 0.5500 M solution of HNO3. The pKb of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 249.4mL of the HNO3 solution to it.
use:
pKb = -log Kb
3.33= -log Kb
Kb = 4.677*10^-4
Given:
M(HNO3) = 0.55 M
V(HNO3) = 249.4 mL
M((CH3)2CHNH2) = 0.68 M
V((CH3)2CHNH2) = 228.9 mL
mol(HNO3) = M(HNO3) * V(HNO3)
mol(HNO3) = 0.55 M * 249.4 mL = 137.17 mmol
mol((CH3)2CHNH2) = M((CH3)2CHNH2) * V((CH3)2CHNH2)
mol((CH3)2CHNH2) = 0.68 M * 228.9 mL = 155.652 mmol
We have:
mol(HNO3) = 137.17 mmol
mol((CH3)2CHNH2) = 155.652 mmol
137.17 mmol of both will react
excess (CH3)2CHNH2 remaining = 18.482 mmol
Volume of Solution = 249.4 + 228.9 = 478.3 mL
[(CH3)2CHNH2] = 18.482 mmol/478.3 mL = 0.0386 M
[(CH3)2CHNH3+] = 137.17 mmol/478.3 mL = 0.2868 M
They form basic buffer
base is (CH3)2CHNH2
conjugate acid is (CH3)2CHNH3+
Kb = 4.677*10^-4
pKb = - log (Kb)
= - log(4.677*10^-4)
= 3.33
use:
pOH = pKb + log {[conjugate acid]/[base]}
= 3.33+ log {0.2868/3.864*10^-2}
= 4.201
use:
PH = 14 - pOH
= 14 - 4.2005
= 9.7995
Answer: 9.80
An analytical chemist is titrating 228.9 mL of a 0.6800 M solution of isopropylamine ((CH3)2CHNH2) with...
An analytical chemist is titrating 97.2 mL of a 0.1000 M solution of isopropylamine ((CH3),CHNH2) with a 0.8100 M solution of HNO3. The pK, of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 5.4 ml of the HNO2 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places. PHE...
An analytical chemist is titrations 170.7 ml of a 0.86 M solution of isopropylamine with a 0.81 M solution oh HNO3. Pkb of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 54.8 ml of HNO3.
An analytical chemist is titrating 149.2 ml of a 0.2200 M solution of isopropylamine ((CH).CHNH, with a 0.5500 M solution of HNO, The pk of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 66.0 mL of the HNO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO, solution added. Round your answer to 2 decimal places. pH...
An analytical chemist is titrating 75.6mL of a 0.8200M solution of isopropylamine CH32CHNH2 with a 0.5300M solution of HIO3. The pKb of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 132.8mL of the HIO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HIO3 solution added. Round your answer to 2 decimal places. An analytical chemist is titrating...
An analytical chemist is titrating 72.3mL of a 0.2100M solution of isopropylamine CH32CHNH2 with a 0.1800M solution of HNO3. The pKb of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 90.2mL of the HNO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places.
An analytical chemist is titrating 209.0 ml of a 0.7700 M solution of isopropylamine ((CH), CHNH,) with a 0.5300 M solution of HIO;. The pK, of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 337.8 ml of the HIO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HIO; solution added. Round your answer to 2 decimal places....
An analytical chemist is titrating 67.6 mL of a 0.1800M solution of trimethylamine ((CH3)3N) with a 0.7700M solution of HNO3. The pKb of trimethylamine is 4.19. calculate the pH of the base solution after the chemist has added 17.9 mL of the HNO3 solution to it.
An analytical chemist is titrating 109.2 mL of a 0.7500 M solution of trimethylamine ((CH3)3N) with a 0.5000 ΠΌ solution of HN03. The pKb Of trimethylamine is 4.19. Calculate the pH of the base solution after the chemist has added 178.6 mL of the HNO, solution to it alo Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO, solution added. Round your answer to 2 decimal places.
An analytical chemist is titrating 120.0mL of a 0.5200 M solution of diethylamine ((C2H5)2NH) with a 0.07300 M solution of HNO3. The pKb of diethylamine is 2.89. Calculate the pH of the base solution after the chemist has added 395.6mL of HNO3 solution to it.
An analytical chemist is titrating 227.4mL of a 0.5200M solution of ammonia NH3 with a 0.5400M solution of HNO3. The pKb of ammonia is 4.74. Calculate the pH of the base solution after the chemist has added 230.7mL of the HNO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3solution added. Round your answer to 2 decimal places. An analytical chemist is titrating 227.4...