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< Problem Set #5 (Ch 15) Exercise 15.33 Write an equilibrium expression for each of the following chemical equations involvin
Part A coz (aq) + H20 (1) = HCO3 (aq) + OH(aq) CO) 0 Kea- HCO, OH ) [HCO, Keq = H0] Keq = HCO, OH | CO Keq = ico HCO3 H20 CO;
Part B. 2 KCIO: (5) 2 KCl (s) + 3 02 (8) K KCIO, Keq=KCIO! Keq KO! KCIO,12 Keq - (02] K K20,12 KCIO KCIO] Keq - KCIJO, K - (
Submit Request Answer - Part HF (aq) + H20 (1) = H3O(aq) + F (aq) Keq = HF HOT H:0][F] OK - (HF] H,O] е Кеч - H,0 JP 1 Keq =
Submit Request Answer Part D NH, (aq) + H2O (1) = NH4+ (aq) + OH(aq) Keg - 1420 Keq = [H0] O Keq =- (NH (OH) NH3] 2 INH, OH K
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Answer #1

For a reaction at equilibrium : . aA + bB eC + dD Where, a, b, e, d are coefficients from balanced I equation. Equilibrium cokeq = Part-B : 2 keloz (S) t 2 kel(s) + 302(g) [kel]² [ og]? - [Kelog] 2 Keloz & Kel are pure solid so they excluded from keqPart-D: NH3(aq) + H2O(l) + Nhat caq) + oH lag : keq = [NHA] [on] [NH3] [H₂o INH or I canswer) [NH3] Dater excluded from water

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