Question

3. How many atoms are in each of the following? a. 7.75 moles of carbon tetrahydride, CH4 b. 0.0888 moles of carbon monoxide c. 75.00g of calcium nitrate d. The number of hydrogen atoms in 15.00g of ammonium hydrogen phosphate e. The number of carbon atoms in 15.00g calcium acetate f. The number of oxygen atoms in 15.00g of dinitrogen tetroxide 1 Rotorming the man of one of the following

Answer 1

Auswer (as chu, Molar mass of eth = 16.04 g/moli I. 1 mole of city contains 6.023x102s atom 7.75 moles of carbon tetrahy arise, City contaim 6.02981023 x 7.75 . = 4.67X1024 atoms. (6) 1 mol contain I mole carbon monooxide 6.023x16 23 atom contains 0:0888 molen of carbon monoxide = 6:023 X 1023x0.0888 1. = 5.35x10 22 atoms. 010888 mole co has 5.35*1022 atous, (6) Molar mass of calcium nitrate = 164.088 81 ano :: 75.000 of Ca(NO3), 3 75 2 164.088 = 0.46 molens .: more ca(NO3)2 contains 6.023x1025. atsins 1. 0.46 moleo carnos contain 61023x10 23 x 0.46: = 2:77 x 1023 atom ... 75.00g of calcium nitrate has 2.27 x 1023 atoms

Molar man of ammonium hydrogen phosphere (AHY), Hpoy = 132.0562 g/inoy i. 15.000 (NH4), Hpoy en - 0'll mole. . 1320572 i moles of CN Hula Hoon has fio23x1025 atoms .. 0'11 mola why), Hpoy has 6.023*10*011 B 6184 1022 I mokcure of (NH4)₂ H Poy has a hatous. so, in 18g (NH4) tpoy has 4x6.844100 26.15*1023 my drogen atom. le.) Molar man of calcium acetate = 158.17 g/mol Isg calciumacetere a 15 0.09 hits - 158.17 = 0.095 nolen mole calcium acetate contain 6.823x10 arous 0.095 mole calcium acetate contains 6.023x102 10.095 =5.7141022 atom. 1 sleculs, caliism, acette сунъ аоч has 4 coatom.. ist 15.00 û calciumacetere has 14* 5.74x1024) > 2128 *10% carton atoms.

Molar mass of dinitrogen tetraox of dinitrogen tetraoxide, Neoy C is 92.011 otanol. 15.00 g Ngon -- 92.011 m = 0.16 moles of N2Oy .. - I mole nroy contains 6.023x1025 atous 0.16moles Neay contains 6.023x102s +0.16 = 9.63x1022 atom. are molecule of Ne Oy has fous oxygent . 15.000 Neoy has (9.63x1022x4) = 3.85 * 1023 atoms of oxygen, comment] please like and