Question

1) Determine the pH of a solution that is 0.00270M HCl and 0.0215 M HClO2. The Ka of HClO2 is 1.1×10^-2

2) A certain weak base has a Kb of 8.10×10−7. What concentration of this base will produce a pH of 10.31?

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Answer 1

17 qere, Hel is a strong acid there fore it will dissociate completely Hel - H t t cu Since, complete dissociation takes place sog concentration of Hcl a concentration of it [n] = [ut] ve. [ht] = 0.0027M. Now, since Helo, is a weak acid complete dissociation will not take place so, it will dissociate in the following anner: Ht+ clog еаruul to o oo 21 м - w w Heloz Иом [н'] bе we get it above, ut & clož 0.0027 o Helo, 0.0215 Initial ta tn concentration a + change 010027 tx final concentration 010215-a (0.00 27 +x) (x) (0.0215- ka = [H 2 clor ГНclub 27

1.1 x 102 = (0.0022 +2) (a) To 10215-x) Solving the above equation we get the value of a = 0.00997 U [H +] = concentration of H+ = 0.00 27 + x = 0.0027 + 0.00997 = 0.01267 M PH = -log(nt) PH = -log (0 : 01267) a 1.8972 2 Here, Kb = 8. 10x lo- 7 PH = 10:31 Nowa HB + OH- B + H₂O - Kb = [HB] [04 [B] we know that PH + POH = 14 POH + 10.31 = 14 Pol = 14 - 10.31 = 3.69

Рон - bя Фи) (04-) = 10-P м 10 - 3. 69 - 2. 041 х 10 No wa В и 20 , HB +он К- в том ) ГЕ“ Інв] - Фи) - з очі хоч к» Гооч хо- в 8. | о хра (2. очі хоч в) очко в) ( 80 X 107 = xoie ats е б. оЅTА M Cans)
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